JEE Mains · Maths · STD 12 - 7.1 indefinite integral
If \(\int \frac{\mathrm{d} \theta}{\cos ^{2} \theta(\tan 2 \theta+\sec 2 \theta)}=\lambda \tan \theta+2 \log _{\mathrm{e}}|\mathrm{f}(\theta)|+\mathrm{C}\) where \(\mathrm{C}\) is a constant of integration, then the ordered pair \((\lambda, f(\theta))\) is equal to
- A \((-1,1+\tan \theta)\)
- B \((-1,1-\tan \theta)\)
- C \((1,1-\tan \theta)\)
- D \((1,1+\tan \theta)\)
Answer & Solution
Correct Answer
(A) \((-1,1+\tan \theta)\)
Step-by-step Solution
Detailed explanation
\(\mathrm{I}=\int \frac{\mathrm{d} \theta}{\cos ^{2} \theta(\tan 2 \theta+\sec 2 \theta)}\)…
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