JEE Mains · Physics · STD 12 - Magnetism and matter
- JEE Mains 2023
- Easy
- MCQ
A solenoid of \(1200\) turns is wound uniformly in a single layer on a glass tube \(2\,m\) long and \(0.2\,m\) in diameter. The magnetic intensity at the center of the solenoid when a current of \(2\,A\) flows through it is:
Pick an option to check your answer.
Answer & Solution
Correct Answer
(B) \(1.2 \times 10^3\,A m ^{-1}\)
Step-by-step Solution
Detailed explanation
Magnetic field at centre inside the solenoid is given by
\(B =\mu_0 nI\)
So magnetic intensity at centre
\(H =\frac{ B }{\mu_0}= nI =\left(\frac{1200}{2}\right)(2)\)
\(H =1.2 \times 10^3\,Am ^{-1}\)
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