JEE Mains · Physics · STD 12 - 5. Magnetism and matter
A solenoid of \(1200\) turns is wound uniformly in a single layer on a glass tube \(2\,m\) long and \(0.2\,m\) in diameter. The magnetic intensity at the center of the solenoid when a current of \(2\,A\) flows through it is:
- A \(2.4 \times 10^3\,A m ^{-1}\)
- B \(1.2 \times 10^3\,A m ^{-1}\)
- C \(1\,A m ^{-1}\)
- D \(2.4 \times 10^{-3}\,A m ^{-1}\)
Answer & Solution
Correct Answer
(B) \(1.2 \times 10^3\,A m ^{-1}\)
Step-by-step Solution
Detailed explanation
Magnetic field at centre inside the solenoid is given by \(B =\mu_0 nI\) So magnetic intensity at centre \(H =\frac{ B }{\mu_0}= nI =\left(\frac{1200}{2}\right)(2)\) \(H =1.2 \times 10^3\,Am ^{-1}\)
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