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JEE Mains · Physics · STD 12 - Magnetism and matter
  • JEE Mains 2023
  • Easy
  • MCQ

A solenoid of \(1200\) turns is wound uniformly in a single layer on a glass tube \(2\,m\) long and \(0.2\,m\) in diameter. The magnetic intensity at the center of the solenoid when a current of \(2\,A\) flows through it is:

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Answer & Solution

Correct Answer

(B) \(1.2 \times 10^3\,A m ^{-1}\)

Step-by-step Solution

Detailed explanation

Magnetic field at centre inside the solenoid is given by

\(B =\mu_0 nI\)

So magnetic intensity at centre

\(H =\frac{ B }{\mu_0}= nI =\left(\frac{1200}{2}\right)(2)\)

\(H =1.2 \times 10^3\,Am ^{-1}\)

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