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JEE Mains · Physics · STD 11 - Units,dimensions and measurement
  • JEE Mains 2025
  • Easy
  • MCQ

If \(\epsilon_0\) denotes the permittivity of free space and \(\Phi_{\mathrm{E}}\) is the flux of the electric field through the area bounded by the closed surface, then dimension of \(\left(\epsilon_0 \frac{\mathrm{~d} \phi_{\mathrm{E}}}{\mathrm{dt}}\right)\) are that of :

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Answer & Solution

Correct Answer

(D) Electric current

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Detailed explanation

We know that formula for displacement current is given by
\(\mathrm{id}=\varepsilon_0 \frac{\mathrm{~d} \phi_{\varepsilon}}{\mathrm{dt}}\)
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