JEE Mains · Physics · STD 11 - Units,dimensions and measurement
- JEE Mains 2025
- Easy
- MCQ
If \(\epsilon_0\) denotes the permittivity of free space and \(\Phi_{\mathrm{E}}\) is the flux of the electric field through the area bounded by the closed surface, then dimension of \(\left(\epsilon_0 \frac{\mathrm{~d} \phi_{\mathrm{E}}}{\mathrm{dt}}\right)\) are that of :
Pick an option to check your answer.
Answer & Solution
Correct Answer
(D) Electric current
Step-by-step Solution
Detailed explanation
We know that formula for displacement current is given by
\(\mathrm{id}=\varepsilon_0 \frac{\mathrm{~d} \phi_{\varepsilon}}{\mathrm{dt}}\)
\(\mathrm{id}=\varepsilon_0 \frac{\mathrm{~d} \phi_{\varepsilon}}{\mathrm{dt}}\)
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