JEE Mains · Physics · STD 12 -6. Electromagnetic induction
A \(10\,m\) long horizontal wire extends from North East to South West. It is falling with a speed of \(5.0\,ms^{-1},\) at right angles to the horizontal component of the earth’s magnetic field, of \(0.3\times 10^{-4}\,Wb/m^2\). The value of the induced \(emf\) in wire is
- A \(1.5\times 10^{-3}\,V\)
- B \(1.1\times 10^{-3}\,V\)
- C \(2.5\times 10^{-3}\,V\)
- D \(0.3\times 10^{-3}\,V\)
Answer & Solution
Correct Answer
(B) \(1.1\times 10^{-3}\,V\)
Step-by-step Solution
Detailed explanation
\( \therefore \quad \mathrm{Emf} =\mathrm{B} \ell \mathrm{v} \sin 45^{\circ} \) \(=\left(0.3 \times 10^{-4}\right) \times(10) \times 5 \times \frac{1}{\sqrt{2}} \) \(=1.1 \times 10^{-3}\, \mathrm{V} \)
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