JEE Mains · Physics · STD 12 - Ray optics and optical instruments
- JEE Mains 2015
- Hard
- MCQ
A thin convex lens of focal length \('f'\) is put on a plane mirror as shown in the figure. When an object is kept at a distance \('a'\) from the lens - mirror combination, its image is formed at a distance \(\frac{a}{3}\) in front of the combination. The value of \('a'\) is

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Answer & Solution
Correct Answer
(D) \(2f\)
Step-by-step Solution
Detailed explanation
When object is keept at a distance \('a'\) from thin covex lens
By lens formula: \(\frac{1}{v}-\frac{1}{u}=\frac{1}{f}\)
\(\frac{1}{V}-\frac{1}{(-a)}=\frac{1}{f}\)
or, \(\frac{1}{v}=\frac{1}{f}-\frac{1}{a}\) ...... \((i)\)
Mirror forms image at equal distance from mirror
Now, again from lens formula
\(\frac{3}{a}-\frac{1}{V}=\frac{1}{f}\)
\({\frac{3}{a} - \frac{1}{f} + \frac{1}{a} = \frac{1}{f}}\) [From eqn. \((i)\)]
Hence, \(a=2f\)
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