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JEE Mains · Maths · STD 11 - 6. permutation and combination

The largest \( n\in N \) for which \(7^n\) divides 101!, is :

  1. A 16
  2. B 18
  3. C 15
  4. D 19
Verified Solution

Answer & Solution

Correct Answer

(A) 16

Step-by-step Solution

Detailed explanation

Exponent of 7 in 101! \( =[\frac{101}{7}]+[\frac{101}{7^{2}}]+[\frac{101}{7^{3}}]+...... \) \( =14+2=16 \)
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