ExamBro
ExamBro
JEE Mains · Maths · STD 11 - Trigonometrical equations

The angle of elevation of the top of a hill from a point on the horizontal plane passing through the foot of the hill is found to be \(45^{\circ} .\) After walking a distance of \(80\) meters towards the top, up a slope inclined at an angle of \(30^{\circ}\) to the horizontal plane, the angle of elevation of the top of the hill becomes \(75^{\circ} .\) Then the height of the hill (in meters) is

  1. A \(40\)
  2. B \(80\)
  3. C \(120\)
  4. D \(160\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(80\)

Step-by-step Solution

Detailed explanation

\(\tan 75^{\circ}=\frac{ h }{ h +40-40 \sqrt{3}}\) \(\frac{2+\sqrt{3}}{1}=\frac{ h }{ h +40-40 \sqrt{3}}\) \(\Rightarrow 2 h +80-80 \sqrt{3}+\sqrt{3} h +40 \sqrt{3}-120= h\) \(\Rightarrow h (\sqrt{3}+1)=40+40 \sqrt{3}\) \(\Rightarrow h =40\) \(\therefore\) Height of hill…
From JEE Mains
Explore more questions on app