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JEE Mains · Maths · STD 12 - 11. three dimension geometry

If \(\lambda_1 < \lambda_2\) are two values of \(\lambda\) such that the angle between the planes \(P_1: \vec{r}(3 \hat{ i }-5 \hat{ j }+\hat{ k })=7\) and \(P_2: \vec{r} \cdot(\lambda \hat{i}+\hat{j}-3 \hat{k})=9\) is \(\sin ^{-1}\left(\frac{2 \sqrt{6}}{5}\right)\), then the square of the length of perpendicular from the point \(\left(38 \lambda_1, 10 \lambda_2, 2\right)\) to the plane \(P _1\) is \(...........\).

  1. A \(314\)
  2. B \(312\)
  3. C \(313\)
  4. D \(315\)
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Answer & Solution

Correct Answer

(D) \(315\)

Step-by-step Solution

Detailed explanation

\(P _1=\overrightarrow{ r } \cdot(3 \hat{ i }-5 \hat{ j }+\hat{ k })=7\) \(P _2=\overrightarrow{ r } \cdot(\lambda \hat{ i }+\hat{ j }-3 \hat{ k })=9\) \(\theta=\sin ^{-1}\left(\frac{2 \sqrt{6}}{5}\right)\) \(\Rightarrow \sin \theta=\frac{2 \sqrt{6}}{5}\)…
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