JEE Mains · Maths · STD 11 - 10.1 circle and system of circle
Let \(A\) be the point \((1,2)\) and \(B\) be any point on the curve \(x^2+y^2=16\). If the centre of the locus of the point \(P\), which divides the line segment \(A B\) in the ratio \(3: 2\) is the point \(C(\alpha, \beta)\), then the length of the line segment \(AC\) is
- A \(\frac{6 \sqrt{5}}{5}\)
- B \(\frac{4 \sqrt{5}}{5}\)
- C \(\frac{2 \sqrt{5}}{5}\)
- D \(\frac{3 \sqrt{5}}{5}\)
Answer & Solution
Correct Answer
(D) \(\frac{3 \sqrt{5}}{5}\)
Step-by-step Solution
Detailed explanation
\(\frac{12 \cos \theta+2}{5}= h \Rightarrow 12 \cos \theta=5 h -2\) \(\frac{12 \sin \theta+4}{5}= k \Rightarrow 12 \sin \theta=5 k \,\,4\) Sq \& add : \(144=(5 h-2) 2+(5 k-4) 2\) \(\left( x -\frac{2}{5}\right)^2+\left( y -\frac{4}{5}\right)^2=\frac{144}{25}\)…
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