JEE Mains · Maths · STD 11 - 9. straight line
Let the equations of two adjacent sides of a parallelogram \(A B C D\) be \(2 x-3 y=-23\) and \(5 x+4 y\) \(=23\). If the equation of its one diagonal \(AC\) is \(3 x +\) \(7 y=23\) and the distance of A from the other diagonal is \(d\), then \(50 d ^2\) is equal to \(........\).
- A \(528\)
- B \(526\)
- C \(529\)
- D \(527\)
Answer & Solution
Correct Answer
(C) \(529\)
Step-by-step Solution
Detailed explanation
\(A\) and \(C\) point will be \((-4,5)\) and \((3,2)\) mid point of \(AC\) will be \(\left(-\frac{1}{2}, \frac{7}{2}\right)\) equation of diagonal \(BD\) is \(y-\frac{7}{2}=\frac{\frac{7}{2}}{-\frac{1}{2}} \quad\left(x+\frac{1}{2}\right)\) \(7 x+y=0\) Distance of \(A\) from…
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