JEE Mains · Maths · STD 11 - 6. permutation and combination
If the number of five digit numbers with distinct digits and \(2\) at the \(10^{\text {th }}\) place is \(336 \mathrm{k}\), then \(\mathrm{k}\) is equal to
- A \(8\)
- B \(6\)
- C \(4\)
- D \(2\)
Answer & Solution
Correct Answer
(A) \(8\)
Step-by-step Solution
Detailed explanation
\(\_ \;\_\;\_\;\underline2\;\_\) No. of five digits numbers \(=\) No. of ways of filling remaining 4 places \(=8 \times 8 \times 7 \times 6\) \(\mathrm{k}=\frac{8 \times 8 \times 7 \times 6}{336}=8\)
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