JEE Mains · Maths · STD 12 - 6. Application of derivatives
if the curves \({y^2} = 6x,9{x^2} + b{y^2} = 16\) intersect each other at right angles , then the value of \(b\) is :
- A \(\frac{7}{2}\)
- B \(4\)
- C \(\frac{9}{2}\)
- D \(6\).
Answer & Solution
Correct Answer
(C) \(\frac{9}{2}\)
Step-by-step Solution
Detailed explanation
\((3)\) Let curve intersect each other at point \(P\left( {{x_1},{y_1}} \right)\) Since, point of intersection is on both the curves, then \(y_1^2 = 6{x_{1\,}}\,\,\,\,\,\,\,\,\,\,\,\,.....\left( i \right)\) and \(9x_1^2 + by_1^2 = 16\,\,\,\,\,\,....\left( {ii} \right)\) Now,…
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