JEE Mains · Maths · STD 12 - 11. three dimension geometry
If \((a, b, c)\) is the image of the point \((1,2,-3)\) in the line, \(\frac{x+1}{2}=\frac{y-3}{-2}=\frac{z}{-1},\) then \(a+b+c\) is equal to
- A \(-1\)
- B \(2\)
- C \(3\)
- D \(1\)
Answer & Solution
Correct Answer
(B) \(2\)
Step-by-step Solution
Detailed explanation
Line is \(\frac{x+1}{2}=\frac{y-3}{-2}=\frac{z}{-1}=\lambda:\) Let point \(R\) is \((2 \lambda-1,-2 \lambda+3,-\lambda)\) Direction ratio of \(PQ \equiv(2 \lambda-2,-2 \lambda+1,3-\lambda)\) \(PQ\) is \(\perp\) to line…
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