JEE Mains · Maths · STD 12 - 10. vector algebra
Let \(\vec{a}\) and \(\overrightarrow{ b }\) be two non-zero vectors perpendicular to each other and \(|\overrightarrow{ a }|=|\overrightarrow{ b }| .\) If \(|\overrightarrow{ a } \times \overrightarrow{ b }|=|\overrightarrow{ a }|,\) then the angle between the vectors \((\vec{a}+\vec{b}+(\vec{a} \times \vec{b}))\) and \(\vec{a}\) is equal to
- A \(\sin ^{-1}\left(\frac{1}{\sqrt{3}}\right)\)
- B \(\cos ^{-1}\left(\frac{1}{\sqrt{3}}\right)\)
- C \(\cos ^{-1}\left(\frac{1}{\sqrt{2}}\right)\)
- D \(\sin ^{-1}\left(\frac{1}{\sqrt{6}}\right)\)
Answer & Solution
Correct Answer
(B) \(\cos ^{-1}\left(\frac{1}{\sqrt{3}}\right)\)
Step-by-step Solution
Detailed explanation
\(|\overrightarrow{ a }|=|\overrightarrow{ b }|,|\overrightarrow{ a } \times \overrightarrow{ b }|=|\overrightarrow{ a }|, \overrightarrow{ a } \perp \overrightarrow{ b }\)…
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