JEE Mains · Maths · STD 11 - 14. probability
Let a computer program generate only the digits \(0\) and \(1\) to form a string of binary numbers with probability of occurrence of \(0\) at even places be \(\frac{1}{2}\) and probability of occurrence of \(0\) at the odd place be \(\frac{1}{3}\). Then the probability that \('10'\) is followed by \('01'\) is equal to :
- A \(\frac{1}{18}\)
- B \(\frac{1}{3}\)
- C \(\frac{1}{6}\)
- D \(\frac{1}{9}\)
Answer & Solution
Correct Answer
(D) \(\frac{1}{9}\)
Step-by-step Solution
Detailed explanation
\(\underset{\text { odd place }}{1} \underset{\text { even place }}{0} \underset{\text { odd place }}{0} \underset{\text { even place }}{1}\)…
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