JEE Mains · Maths · STD 12 - 11. three dimension geometry
The distance of the point \(P (4,6,-2)\) from the line passing through the point \((-3,2,3)\) and parallel to a line with direction ratios \(3,3,-1\) is equal to :
- A \(3\)
- B \(\sqrt{6}\)
- C \(2 \sqrt{3}\)
- D \(\sqrt{14}\)
Answer & Solution
Correct Answer
(D) \(\sqrt{14}\)
Step-by-step Solution
Detailed explanation
Equation of line is \(\frac{x+3}{3}=\frac{y-2}{3}=\frac{z-3}{-1}=\lambda\) \(M (3 \lambda-3,3 \lambda+2,3-\lambda)\) D.R of \(\operatorname{PM}(3 \lambda-7,3 \lambda-4,5-\lambda)\) Since \(P M\) is perpendicular to line…
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