JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
\(\Delta_{\text {vap }} \mathrm{H}^{\ominus}\) for water is \(+40.49 \mathrm{~kJ} \mathrm{~mol}^{-1}\) at 1 bar and \(100^{\circ} \mathrm{C}\). Change in internal energy for this vapourisation under same condition is _______ \(\mathrm{kJ}\) \(\mathrm{mol}^{-1}\). (Integer answer) (Given \(\mathrm{R}=8.3 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}\) )
- A \(38\)
- B \(39\)
- C \(40\)
- D \(45\)
Answer & Solution
Correct Answer
(A) \(38\)
Step-by-step Solution
Detailed explanation
\(\mathrm{H}_2 \mathrm{O}(\ell) \rightleftharpoons \mathrm{H}_2 \mathrm{O}(\mathrm{g}) \quad \Delta \mathrm{H}_{\text {ap }}^0=40.79 \mathrm{~kJ} / \mathrm{mole}\)…
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