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JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties

\(8\,g\) of \(NaOH\) is dissolved in \(18\,g\) of \(H_2O.\) Mole fraction of \(NaOH\) in solution and molality (in \(mol\,kg^{-1}\) ) of the solution respectively are

  1. A \(0.2,\,22.20\)
  2. B \(0.2,\,11.11\)
  3. C \(0.167,\,11.11\)
  4. D \(0.167,\,22.20\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(0.167,\,11.11\)

Step-by-step Solution

Detailed explanation

Moles of \(NaOH\) \(=\,\frac {8}{40}\,=\,0.2\) Moles of \(H_2O\) \(=\,\frac {18}{18}\,=\,1\) Mole fraction of \(NaOH\) \(=\,\frac {0.2}{1.2}\,=\,0.167\) Molality \(=\,\frac {8}{40}\times \frac {1000}{18}=\,11.11\)
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