JEE Mains · Chemistry · STD 11 - 7. Redox reactions
Thiosulphate reacts differently with iodine and bromine in the reaction given below : \( 2 \mathrm{~S}_2 \mathrm{O}_3^{2-}+\mathrm{I}_2 \rightarrow \mathrm{S}_4 \mathrm{O}_6^{2-}+2 \mathrm{I}^{-}\) \(\mathrm{S}_2 \mathrm{O}_3^{2-}+5 \mathrm{Br}_2+5 \mathrm{H}_2 \mathrm{O} \rightarrow 2 \mathrm{SO}_4^{2-}+4 \mathrm{Br}^{-}+10 \mathrm{H}^{+}\) Which of the following statement justifies the above dual behaviour of thiosulphate?
- A Bromine undergoes oxidation and iodine undergoes reduction by iodine in these reactions
- B Thiosulphate undergoes oxidation by bromine and reduction by iodine in these reaction
- C Bromine is a stronger oxidant than iodine
- D Bromine is a weaker oxidant than iodine
Answer & Solution
Correct Answer
(C) Bromine is a stronger oxidant than iodine
Step-by-step Solution
Detailed explanation
In the reaction of \(\mathrm{S}_2 \mathrm{O}_3{ }^{2-}\) with \(\mathrm{I}_2\), oxidation state of sulphur changes to +\(2\) to +\(2.5\) In the reaction of \(\mathrm{S}_2 \mathrm{O}_3{ }^{2-}\) with \(\mathrm{Br}_2\), oxidation state of sulphur changes from +\(2\) to +\(6\) .…
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