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JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties

The vapour pressures of \(A\) and \(B\) at \(25^{\circ} \mathrm{C}\) are \(90\, \mathrm{~mm}\, \mathrm{Hg}\) and \(15\, \mathrm{~mm} \,\mathrm{Hg}\) respectively. If \(\mathrm{A}\) and \(\mathrm{B}\) are mixed such that the mole fraction of \(A\) in the mixture is \(0.6\), then the mole fraction of \(B\) in the vapour phase is \(x \times 10^{-1}\). The value of \(x\) is \(.....\) (Nearest integer)

  1. A \(1\)
  2. B \(2\)
  3. C \(3\)
  4. D \(4\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(1\)

Step-by-step Solution

Detailed explanation

Given \(\mathrm{P}_{\mathrm{A}}^{\circ}=90\, \mathrm{~mm}\, \mathrm{Hg}\), at \(25^{\circ} \mathrm{C}\) \(\mathrm{P}_{\mathrm{B}}^{\circ}=15\, \mathrm{~mm} \,\mathrm{Hg}\) \(\text { and }\mathrm{X}_{\mathrm{A}}=0.6,\mathrm{X}_{\mathrm{B}}=0.4\)…
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