JEE Mains · Chemistry · STD 12 -1. Solution and colligative properties
The vapour pressures of \(A\) and \(B\) at \(25^{\circ} \mathrm{C}\) are \(90\, \mathrm{~mm}\, \mathrm{Hg}\) and \(15\, \mathrm{~mm} \,\mathrm{Hg}\) respectively. If \(\mathrm{A}\) and \(\mathrm{B}\) are mixed such that the mole fraction of \(A\) in the mixture is \(0.6\), then the mole fraction of \(B\) in the vapour phase is \(x \times 10^{-1}\). The value of \(x\) is \(.....\) (Nearest integer)
- A \(1\)
- B \(2\)
- C \(3\)
- D \(4\)
Answer & Solution
Correct Answer
(A) \(1\)
Step-by-step Solution
Detailed explanation
Given \(\mathrm{P}_{\mathrm{A}}^{\circ}=90\, \mathrm{~mm}\, \mathrm{Hg}\), at \(25^{\circ} \mathrm{C}\) \(\mathrm{P}_{\mathrm{B}}^{\circ}=15\, \mathrm{~mm} \,\mathrm{Hg}\) \(\text { and }\mathrm{X}_{\mathrm{A}}=0.6,\mathrm{X}_{\mathrm{B}}=0.4\)…
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