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JEE Mains · Chemistry · STD 12 - 2. Electrochemistry

The variation of equilibrium constant with temperature is given below  Temperature \(\quad\) Equilibrium constant \(\begin{array}{ll} T _{1}=25^{\circ} C & K _{1}=100 \\ T _{2}=100^{\circ} C & K _{2}=100\end{array}\) The values of \(\Delta H ^{\circ}, \Delta G ^{\circ}\) at \(T _{1}\) and \(\Delta G ^{\circ}\) at \(T _{2}\) (in \(kJ\, mol ^{-1}\) ) respectively, are close to \(\left[\right.\) Use \(\left. R =8.314\, JK ^{-1} mol ^{-1}\right]\)

  1. A \(0.64,-5.71\) and \(-14.29\)
  2. B \(28.4,-7.14\) and \(-5.71\)
  3. C \(28.4,-5.71\) and \(-14.29\)
  4. D \(0.64,-7.14\) and \(-5.71\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(28.4,-5.71\) and \(-14.29\)

Step-by-step Solution

Detailed explanation

\(\operatorname{In}\left[\frac{ k _{2}}{ k _{1}}\right]=\frac{\Delta H ^{\circ}}{ R }\left\{\frac{1}{ T _{1}}-\frac{1}{ T _{2}}\right\}\) \(\ln (10)=\frac{\Delta H ^{\circ}}{ R }\left\{\frac{1}{298}-\frac{1}{373}\right\}\)…
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