JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
The photoelectric current from Na (work function, \(\left. w _{0}=2.3\, eV \right)\) is stopped by the output voltage of the cell \(Pt ( s )\left| H _{2}( g , 1 bar )\right| HCl ( aq \cdot, pH =1)| AgCl ( s )| Ag ( s )\) The \(pH\) of aq. HCl required to stop the photoelectric current from \(K \left( w _{0}=2.25 eV \right),\) all other conditions remaining the same, is..........\(\times 10^{-2}\) (to the nearest integer). Given, \(2.303 \frac{ RT }{ F }=0.06 V ; E _{ AgC1|Ag|C ^{-}}^{0}=0.22\, V\)
- A \(146\)
- B \(150\)
- C \(142\)
- D \(154\)
Answer & Solution
Correct Answer
(C) \(142\)
Step-by-step Solution
Detailed explanation
\(\frac{1}{2} H _{2} \rightarrow H ^{+}+ e ^{\ominus}\) \(e ^{\ominus}+ AgCl _{(s)} \rightarrow Ag _{(s)}+ Cl ^{\ominus}\) _______________________________________________________ \(\frac{1}{2} H _{2}+ AgCl _{(s)} \rightarrow H _{( aq )}^{+}+ Ag _{(s)}+ Cl _{( aq )}^{\ominus}\)…
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