JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
Resistance of \(0.2\, M\) solution of an electrolyte is \(50 \Omega .\)The specific conductance of the solution is \(1.4\, S\, m^{-1}.\) The resistance of \(0.5\, M\) solution of the same electrolyte is \(280\, \Omega .\) The molar conductivity of \(0.5\, M\) solution of the electrolyte in \(S\, m^2\, mol^{-1}\) is :
- A \(5 \times 10^{-4}\)
- B \(5 \times 10^{-3}\)
- C \(5 \times 10^{3}\)
- D \(5 \times 10^{2}\)
Answer & Solution
Correct Answer
(A) \(5 \times 10^{-4}\)
Step-by-step Solution
Detailed explanation
Given for \(0.2 \mathrm{M}\) solution \(R=50 \Omega\) \(\kappa=1.45 S m^{-1}=1.4 \times 10^{-2} S \mathrm{cm}^{-1}\) Now, \(R=\rho {\frac{\ell}{a}}=\frac{1}{\kappa} \times \frac{\ell}{a}\) \(\Rightarrow \frac{\ell}{a}=R \times \kappa=50 \times 1.4 \times 10^{-2}\) For \(0.5 M\)…
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