JEE Mains · Chemistry · STD 12 - 9. Amines
In the Hoffmann bromamide degradation reaction, the number of moles of \(NaOH\) and \(Br_2\) used per mole of amine produced are :
- A Two moles of \(NaOH\) and two moles of \(Br_2.\)
- B Four moles of \(NaOH\) and one mole of \(Br_2.\)
- C One mole of \(NaOH\) and one mole of \(Br_2.\)
- D Four moles of \(NaOH\) and two moles of \(Br_2.\)
Answer & Solution
Correct Answer
(B) Four moles of \(NaOH\) and one mole of \(Br_2.\)
Step-by-step Solution
Detailed explanation
Hofmann-bromamide degradation reaction is given as \(\mathrm{RCONH}_{2}+4 \mathrm{NaOH}+\mathrm{Br}_{2} \rightarrow \)\(\mathrm{RNH}_{2}+\mathrm{Na}_{2} \mathrm{CO}_{3}+2 \mathrm{NaBr}+2 \mathrm{H}_{2} \mathrm{O}\) Hence four moles of \(\mathrm{NaOH}\) and one mole of…
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