JEE Mains · Chemistry · STD 11 - 4. Chemical bonding and molecular structure
The total number of electrons in all bonding molecular orbitals of \(O_{2}^{2-}\) is \(....\,.\) (Round off to the Nearest Integer).
- A \(5\)
- B \(10\)
- C \(15\)
- D \(20\)
Answer & Solution
Correct Answer
(B) \(10\)
Step-by-step Solution
Detailed explanation
\(\sigma 1 \mathrm{~s}^{2} \sigma 1^* \mathrm{~s}^{2} \sigma 2 \mathrm{~s}^{2} \sigma 2^* \mathrm{~s}^{2} \sigma 2 \mathrm{p}_{z}^{2} \pi 2 \mathrm{p}_{\mathrm{x}}^{2}=\pi 2 \mathrm{p}_{\mathrm{y}}^{2}\) \(\pi 2^* \mathrm{p}_{\mathrm{x}}^{2}=\pi 2^* \mathrm{p}_{\mathrm{y}}^{2}\)
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