JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
The standard electrode potential \(E^-\) and its temperature coefficient \(\left( {\frac{{d{E^ - }}}{{dT}}} \right)\) for a cell are \(2\,V\) and \(-\,5\times10^{-4}\,V\,K^{-1}\) at \(300\,K\) respectively. The cell reaction is \(Zn\left( s \right) + C{u^{2 + }}\left( {aq} \right) \rightleftharpoons Z{n^{2 + }}\left( {aq} \right) + Cu\left( s \right)\) Standard reaction enthalpy \(\left( {{\Delta _r}{H^ - }} \right)\) ....... \(\mathrm{kJ}\)
- A \(-412.8\)
- B \(-384.0\)
- C \(1920\)
- D \(206.4\)
Answer & Solution
Correct Answer
(A) \(-412.8\)
Step-by-step Solution
Detailed explanation
\(\Delta G\, = \, - \,nFE_{cell}\, = \, - \,2\) \( \times \,96500\, \times \,2\,\, = \, - \,386\,\,kJ\) \(\Delta S=nF\left( \frac{dE}{dT} \right)=2\times 96500\,\,\times (-5\times {{10}^{-4}}J{{/}^{o}}C)=-96.5\,kJ\) at \(298\,K\)…
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