JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
The rate of a reaction \(A\) doubles on increasing the temperature from \(300\) to \(310\, K\). By how much, the temperature of reaction \(B\) should be increased from \(300\, K\) so that rate doubles if activation energy of the reaction \(B\) is twice to that of reaction \(A\). ......... \(K\)
- A \(9.84\)
- B \(4.92\)
- C \(2.45\)
- D \(19.67\)
Answer & Solution
Correct Answer
(B) \(4.92\)
Step-by-step Solution
Detailed explanation
In order to calculate the enthalpy change for \(H_2O\) at \(5\,^oC\) to ice at \(-\,5\,^oC\) , we need to calculated the enthalpy change of all the transformation involved in the process. \((a)\) Energy change of \(1\,mol\), \(H_2O\,(l)\), at \(5\,^oC\) \(\to \,1\,mol\),…
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