JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
\(N_2O_5\) decomposes to \(NO_2\) and \(O_2\) and follows first order kinetics . After \(50\, minutes\), the pressure inside the vessel increases from \(50\, mm\,Hg\) to \(87 .5\, mm \,Hg\). The pressure of the gaseous mixture after \(100\, minutes\) at constant temperature will be ........... \(mm\,Hg\)
- A \(136.25\)
- B \(106.25\)
- C \(175.0\)
- D \(116.25\)
Answer & Solution
Correct Answer
(B) \(106.25\)
Step-by-step Solution
Detailed explanation
\({N_2}{O_5}\, \to \,2N{O_2}\, + \,\frac{1}{2}{O_2}\) At \(t=0\) \(50\) \(0\) \(0\) At \(t=50\,min\) \(50-p_1\) \(2p_1\) \(\frac {p_1}{2}\) Total pressure at \(50\,\min\) \(=\,50-p_1+2p_1+\frac {p_1}{2}=87.5\) \(50+\frac {3p_1}{2}=87.5\) \(\frac{{3{p_1}}}{2}\, = \,37.5\)…
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