JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics
Consider an elementary reaction
\(\mathrm{A}(\mathrm{g})+\mathrm{B}(\mathrm{g}) \rightarrow \mathrm{C}(\mathrm{g})+\mathrm{D}(\mathrm{g})\)
If the volume of reaction mixture is suddenly reduced to \(\frac{1}{3}\) of its initial volume, the reaction rate will become ' \(x\) ' times of the original reaction rate. The value of \(x\) is :
- A \(3\)
- B \(\frac{1}{9}\)
- C \(9\)
- D \(\frac{1}{3}\)
Answer & Solution
Correct Answer
(C) \(9\)
Step-by-step Solution
Detailed explanation
Since, the reaction is elementary \(\text { Rate }=k[A]^1[B]^1\) When V is reduced to \(\frac{1}{3} \mathrm{~V}\), concentration will be tripled. Hence, rate \(=9 \times(\text { rate })_{\text {initial }}\) \(x=9\)
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