JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
A solution of \(\mathrm{H}_2 \mathrm{SO}_4\) is \(31.4 \% \mathrm{H}_2 \mathrm{SO}_4\) by mass and has a density of \(1.25 \mathrm{~g} / \mathrm{mL}\). The molarity of the \(\mathrm{H}_2 \mathrm{SO}_4\) solution is _______ \( \mathrm{M}\) (nearest integer)[Given molar mass of \(\mathrm{H}_2 \mathrm{SO}_4=98 \mathrm{~g} \mathrm{~mol}^{-1}\) ]
- A \(4\)
- B \(3\)
- C \(2\)
- D \(1\)
Answer & Solution
Correct Answer
(A) \(4\)
Step-by-step Solution
Detailed explanation
\( \mathrm{M}=\frac{\mathrm{n}_{\text {solute }}}{\mathrm{V}} \times 1000 \) \( =\frac{\left(\frac{31.4}{98}\right)}{\left(\frac{100}{1.25}\right)} \times 1000 \) \( =4.005 \approx 4\)
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