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JEE Mains · Chemistry · STD 12 - 3. Chemical kinetics

The rate constant for a first order reaction is \(20\,min ^{-1}\). The time required for the initial concentration of the reactant to reduce to its \(\frac{1}{32}\) level is \(........\times 10^{-2}\,min\). (Nearest integer)(Given: \(\quad \ln 10=2.303, \log 2=0.3010)\)

  1. A \(16\)
  2. B \(15\)
  3. C \(17\)
  4. D \(14\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(17\)

Step-by-step Solution

Detailed explanation

\(C=\frac{C_o}{2^n}=\frac{C_o}{32}\) \(n =5\) \(t =5 t _{1 / 2}\) \(=\frac{5 \times 0.693}{20}=\frac{0.693}{4}\) \(=0.17325\,min =17.325 \times 10^{-2}\,min\)
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