JEE Mains · Physics · STD 12 - Electric potential and capacitance
- JEE Mains 2013
- Medium
- MCQ
Two capacitors \(C_1\) and \(C_2\) are charged to \(120\ V\) and \(200\ V\) respectively. It is found that connecting them together the potential on each one can be made zero. Then
Pick an option to check your answer.
Answer & Solution
Correct Answer
(C) \(3C_1=5C_2\)
Step-by-step Solution
Detailed explanation
For potential to be made zero, after connection
\(120 \mathrm{C}_{1}=200 \mathrm{C}_{2} \quad\left[\because C=\frac{q}{v}\right]\)
\(\Rightarrow \quad 3 C_{1}=5 C_{2}\)
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