JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
\(5\, moles\) of \(AB_2\) weight \(125 \times 10^{-3}\, kg\) and \(10\, moles\) of \(A_2B_2\) weight \(300 \times 10^{-3}\, kg\). The molar mass of \(A(M_A)\) and molar mass of \(B(M_B)\) in \(kg\, mol^{-1}\) are
- A \({M_A} = 50 \times {10^{ - 3}}\) and \({M_B} = 25 \times {10^{ - 3}}\)
- B \({M_A} = 10 \times {10^{ - 3}}\) and \({M_B} = 5 \times {10^{ - 3}}\)
- C \({M_A} = 5 \times {10^{ - 3}}\) and \({M_B} = 10 \times {10^{ - 3}}\)
- D \({M_A} = 25 \times {10^{ - 3}}\) and \({M_B} = 50 \times {10^{ - 3}}\)
Answer & Solution
Correct Answer
(C) \({M_A} = 5 \times {10^{ - 3}}\) and \({M_B} = 10 \times {10^{ - 3}}\)
Step-by-step Solution
Detailed explanation
Mol. wt is of \(1\, mol\) \(AB_2\) \(A + 2B = 25\) \(A_2B_2\) \(2A + 2B = 30\)
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from Chemistry
- Ferrous sulphate heptahydrate is used to fortify foods with iron. The amount (in \(grams\)) of the salt required to achieve \(10 \;ppm\) of iron in \(100 \;\mathrm{kg}\) of wheat is Atomic weight : \(Fe =55.85 ; \mathrm{S}=32.0\) \(\mathrm{O}=16.00\)JEE Mains 2020 Hard
- The correct order of stability of following carbocations is :
JEE Mains 2025 Easy - In Duma's method of estimation of nitrogen, \(0.1840 \,g\) of an organic compound gave \(30 \,mL\) of nitrogen collected at \(287\, K\) and \(758\, mm\) of \(Hg\) pressure. The percentage composition of nitrogen in the compound is ...... . (Round off to the Nearest Integer). [Given : Aqueous tension at \(287\, K =14 \,mm\) of \(Hg\) ]JEE Mains 2021 Hard
- At \(298.2\, \mathrm{~K}\) the relationship between enthalpy of bond dissociation (in \(\mathrm{kJ} \,\mathrm{mol}^{-1}\) ) for hydrogen \(\left(\mathrm{E}_{\mathrm{H}}\right)\) and its isotope, deuterium \(\left(\mathrm{E}_{\mathrm{D}}\right)\), is best described by:JEE Mains 2021 Hard
- The rate of a reaction \(A\) doubles on increasing the temperature from \(300\) to \(310\, K\). By how much, the temperature of reaction \(B\) should be increased from \(300\, K\) so that rate doubles if activation energy of the reaction \(B\) is twice to that of reaction \(A\). ......... \(K\)JEE Mains 2017 Hard
- \(0.5\,g\) of an organic compound \((X)\) with \(60 \%\) carbon will produce \(........\times 10^{-1}\, g\) of \(CO _2\) on complete combustion.JEE Mains 2023 Medium
More PYQs from JEE Mains
- Let three vectors \(\overrightarrow{ a }, \overrightarrow{ b }\) and \(\overrightarrow{ c }\) be such that \(\overrightarrow{ c }\) is coplanar with \(\overrightarrow{ a }\) and \(\overrightarrow{ b }, \overrightarrow{ a } \cdot \overrightarrow{ c }=7\) and \(\overrightarrow{ b }\) is perpendicular to \(\overrightarrow{ c },\) where \(\overrightarrow{ a }=-\hat{ i }+\hat{ j }+\hat{ k }\) and \(\overrightarrow{ b }=2 \hat{ i }+\hat{ k },\) then the value of \(2|\overrightarrow{ a }+\overrightarrow{ b }+\overrightarrow{ c }|^{2}\) is .........JEE Mains 2021 Hard
- Total number of ions from the following with noble gas configuration is__________. \( \mathrm{Sr}^{2+}(\mathrm{Z}=38), \mathrm{Cs}^{+}(\mathrm{Z}=55), \mathrm{La}^{2+}(\mathrm{Z}=57) \mathrm{Pb}^{2+} \) \( (\mathrm{Z}=82), \mathrm{Yb}^{2+}(\mathrm{Z}=70) \text { and } \mathrm{Fe}^{2+}(\mathrm{Z}=26)\)JEE Mains 2024 Hard
- Let \(\lambda \in R .\) The system of linear equations \(2 x_{1}-4 x_{2}+\lambda x_{3}=1\) \(x_{1}-6 x_{2}+x_{3}=2\) \(\lambda x_{1}-10 x_{2}+4 x_{3}=3\) is inconsistent forJEE Mains 2020 Hard
- If the matrix \(A=\left(\begin{array}{cc}0 & 2 \\ K & -1\end{array}\right)\) satisfies \(A\left(A^{3}+3 I\right)=2 I\) then the value of \(\mathrm{K}\) is :JEE Mains 2021 Hard
- The number of \(f\) electrons in the ground state electronic configuration of \(\mathrm{Np}(\mathrm{Z}=93)\) is ....... .JEE Mains 2021 Easy
- The rms speed of oxygen molecule in a vessel at particular temperature is \(\left(1+\frac{5}{x}\right)^{\frac{1}{2}} v\), where \(v\) is the average speed of the molecule. The value of \(x\) will be:(Take \(\pi=\frac{22}{7}\) )JEE Mains 2023 Medium