JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
The Molarity \((M)\) of an aqueous solution containing \(5.85 \mathrm{~g}\) of \(\mathrm{NaCl}\) in \(500 \mathrm{~mL}\) water is _______. (Given : Molar Mass \(\mathrm{Na}: 23\) and \(\mathrm{Cl}: 35.5 \mathrm{gmol}^{-1}\) )
- A \(20\)
- B \(0.2\)
- C \(2\)
- D \(4\)
Answer & Solution
Correct Answer
(B) \(0.2\)
Step-by-step Solution
Detailed explanation
\(\mathrm{M}=\frac{\mathrm{n}_{\mathrm{NaCl}}}{\mathrm{V}_{\mathrm{sol}}(\text { in } \mathrm{L})}\) \(\mathrm{M}=\frac{\frac{5.85}{58.5}}{0.5}=0.2 \mathrm{M}\)
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