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JEE Mains · Physics · STD 12 - 8. Electromagnetic waves
For plan electromagnetic waves propagating in the \(z-\) direction, which one of the following combination gives the correct possible direction for \(\vec E\) and \(\vec B\) field respectively?
- A \(\left( {2\hat i + 3\hat j} \right)\) and \(\left( {\hat i + 2\hat j} \right)\)
- B \(\left( {-2\hat i - 3\hat j} \right)\) and \(\left( {3\hat i - 2\hat j} \right)\)
- C \(\left( {3\hat i + 4\hat j} \right)\) and \(\left( {4\hat i - 3\hat j} \right)\)
- D \(\left( {\hat i + 2\hat j} \right)\) and \(\left( {2\hat i - \hat j} \right)\)
Answer & Solution
Correct Answer
(B) \(\left( {-2\hat i - 3\hat j} \right)\) and \(\left( {3\hat i - 2\hat j} \right)\)
Step-by-step Solution
Detailed explanation
As we know, \(\vec E \cdot \vec B = 0\) \(\because [\vec E \bot \vec B]\) and \(\vec{E} \times \vec{B}\) should be along \(Z\) direction As \((-2 \hat{i}-3 \hat{j}) \times(3 \hat{i}-2 \hat{j})=13 \hat{k}\) Hence option \((b)\) is the correct answer.
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