JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
The mass of sodium acetate \(\left(\mathrm{CH}_3 \mathrm{COONa}\right)\) required to prepare \(250 \mathrm{~mL}\) of \(0.35\ \mathrm{M}\) aqueous solution is _______\(g\). (Molar mass of \(\mathrm{CH}_3 \mathrm{COONa}\) is \(82.02 \mathrm{~g} \mathrm{~mol}^{-1}\) )
- A \(6\)
- B \(7\)
- C \(8\)
- D \(9\)
Answer & Solution
Correct Answer
(B) \(7\)
Step-by-step Solution
Detailed explanation
\(\text { Moles }=\text { Molarity } \times \text { Volume in litres }\) \(=0.35 \times 0.25\) \(\text { Mass }=\text { moles } \times \text { molar mass }\) \(=0.35 \times 0.25 \times 82.02=7.18 \mathrm{~g}\) Ans. 7
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