JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
The heat of solution of anhydrous \(\mathrm{CuSO}_4\) and \(\mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O}\) are \(-70 \mathrm{~kJ} \mathrm{~mol}^{-1}\) and \(+12 \mathrm{~kJ} \mathrm{~mol}^{-1}\) respectively. The heat of hydration of \(\mathrm{CuSO}_4\) to \(\mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O}\) is \(-\mathrm{xkJ}\). The value of \(\mathrm{x}\) is _______.
- A \(82\)
- B \(85\)
- C \(89\)
- D \(90\)
Answer & Solution
Correct Answer
(A) \(82\)
Step-by-step Solution
Detailed explanation
\(\text {from (1) (2) }\) \(-70=x+12\) \(x=-82\)
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