JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
The heat of combustion of solid benzoic acid at constant volume is \(-321.30 \mathrm{~kJ}\) at \(27^{\circ} \mathrm{C}\). The heat of combustion at constant pressure is \((-321.30-x R)\) \(\mathrm{kJ}\), the value of \(\mathrm{x}\) is _______.
- A \(100\)
- B \(120\)
- C \(150\)
- D \(160\)
Answer & Solution
Correct Answer
(C) \(150\)
Step-by-step Solution
Detailed explanation
\(\mathrm{C}_6 \mathrm{H}_5 \mathrm{COOH}(\mathrm{S})+\frac{15}{2} \mathrm{O}_2(\mathrm{~g}) \rightarrow 7 \mathrm{CO}_2(\mathrm{~g})+3 \mathrm{H}_2 \mathrm{O}(\ell)\) \(\Delta \mathrm{H}=\Delta \mathrm{U}+\Delta \mathrm{n}_g \mathrm{RT}\)…
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