JEE Mains · Chemistry · STD 12 - 9. Amines
When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid ( 273 K) and acidified with acetic acid, the mass ( g) of 0.1 mole of product formed is _______.
(Given molar mass in \(\mathrm{g} \mathrm{mol}^{-1} \mathrm{H}: 1, \mathrm{C}: 12, \mathrm{~N}: 14\), \(\mathrm{O}: 16, \mathrm{~S}: 32)\)
- A 343
- B 330
- C 33
- D 66
Answer & Solution
Correct Answer
(C) 33
Step-by-step Solution
Detailed explanation
0.1 mole of red-azo dye \((\) Molar Mass \(=327 \mathrm{gm} / \mathrm{mol})\) will have 32.7 gm mass. Nearly 33 gm.
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