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JEE Mains · Chemistry · STD 12 - 9. Amines

When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid ( 273 K) and acidified with acetic acid, the mass ( g) of 0.1 mole of product formed is _______.
(Given molar mass in \(\mathrm{g} \mathrm{mol}^{-1} \mathrm{H}: 1, \mathrm{C}: 12, \mathrm{~N}: 14\), \(\mathrm{O}: 16, \mathrm{~S}: 32)\)

  1. A 343
  2. B 330
  3. C 33
  4. D 66
Verified Solution

Answer & Solution

Correct Answer

(C) 33

Step-by-step Solution

Detailed explanation

0.1 mole of red-azo dye \((\) Molar Mass \(=327 \mathrm{gm} / \mathrm{mol})\) will have 32.7 gm mass. Nearly 33 gm.
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