JEE Mains · Chemistry · STD 11 - 6.2. Equilibrium - II (icon Equilibrium)
The \(\mathrm{pH}\) of a solution obtained by mixing \(50 \,\mathrm{~mL}\) of \(1\, \mathrm{M}\, \mathrm{HCl}\) and \(30 \,\mathrm{~mL}\) of \(1\, \mathrm{M} \,\mathrm{NaOH}\) is \(\mathrm{x} \times 10^{-4}\). The value of \(\mathrm{x}\) is ...... . (Nearest integer) \([\log 2.5=0.3979]\)
- A \(5021\)
- B \(6021\)
- C \(2211\)
- D \(3211\)
Answer & Solution
Correct Answer
(B) \(6021\)
Step-by-step Solution
Detailed explanation
\(\quad\quad\quad\mathrm{HCl}(\) aq. \()+\mathrm{NaOH}\) (aq.) \(\rightarrow \mathrm{NaCl}(\) aq. \()+\mathrm{H}_{2} \mathrm{O}(\ell)\) \(\quad\quad\quad50\, \mathrm{ml}, 1\, \mathrm{M} \quad 30\, \mathrm{ml}, 1\, \mathrm{M} \quad\quad\quad\quad-\quad\quad\quad\quad\quad-\)…
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