JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry
\(10\, mL\) of \(1\,mM\) surfactant solution forms a monolayer covering \(0.24\, cm^2\) on a polar substrate. If the polar head is approximated as cube, what is its edge length ?
- A \(2.0\,pm\)
- B \(2.0\,nm\)
- C \(1.0\,pm\)
- D \(0.1\,nm\)
Answer & Solution
Correct Answer
(A) \(2.0\,pm\)
Step-by-step Solution
Detailed explanation
\(Moles = \frac{{MV\,ml}}{{1000}} = \frac{{{{10}^{ - 3}} \times 10}}{{1000}} = {10^{ - 5}}\,mole\) \(10^{-5}\) \(N_A\) molecules covering area \(= 0.24\,cm^2\) \(1\) molecules covering area \( = \frac{{0.24}}{{{{10}^{ - 5}}\,{N_A}}}\)…
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