JEE Mains · Chemistry · STD 11 - 4. Chemical bonding and molecular structure
The covalency and oxidation state respectively of boron in \(\left[ BF _4\right]^{-}\), are
- A \(4\) and \(3\)
- B \(4\) and \(4\)
- C \(3\) and \(4\)
- D \(3\) and \(5\)
Answer & Solution
Correct Answer
(A) \(4\) and \(3\)
Step-by-step Solution
Detailed explanation
Number of covalent bond formed by Boron is \(4\) Oxidation number of fluorine is \(-1\), Oxidation number of \(B +4 \times(-1)=-1\), Thus, Oxidation number of \(B =+3\)
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