JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
The equation that is incorrect is
- A \(\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{NaBr}}-\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{NaI}}=\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{KBr}}-\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{NaBr}}\)
- B \(\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{H}_{2} \mathrm{O}}=\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{HCl}}+\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{NaOH}}-\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{NaCl}}\)
- C \(\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{KCl}}-\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{NaCl}}=\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{KBr}}-\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{NaBr}}\)
- D \(\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{NaBr}}-\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{NaCl}}=\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{KBr}}-\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{KCl}}\)
Answer & Solution
Correct Answer
(A) \(\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{NaBr}}-\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{NaI}}=\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{KBr}}-\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{NaBr}}\)
Step-by-step Solution
Detailed explanation
According to Kohlrausch's law correct expression \(\overline{15}\)…
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