JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
Gaseous \(N_2O_4\) dissociates into gaseous \(NO_2\) according to the reaction \([{N_2}{O_4}\,(g)\, \rightleftharpoons \,2N{o_2}(g)]\) At \(300\,K\) and \(1\,atm\) pressure, the degree of dissociation of \(N_2O_4\) is \(0.2.\) If one mole of \(N_2O_4\) gas is contained in a vessel, then the density of the equilibrium mixture is.......\(g/L\)
- A \(1.56\)
- B \(6.22\)
- C \(3.11\)
- D \(4.56\)
Answer & Solution
Correct Answer
(C) \(3.11\)
Step-by-step Solution
Detailed explanation
\(\mathop {\mathop {\,\,\,}\limits_{t = 0} }\limits_{t = equilibrium} \mathop {\mathop {{N_2}{O_4}(g)}\limits_1 }\limits_{1 - \alpha } \leftrightarrow \mathop {\mathop {2N{O_2}(g)}\limits_0 }\limits_{2\alpha } \) Where \(\alpha =\) Degree of dissociation. Mol. wt. of mixture…
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