JEE Mains · Chemistry · STD 11 - 2. structure of atom
The de-Broglie's wavelength of an electron in the \(4^{\text {th }}\) orbit is _______. \(\pi a_0 .\left(a_0=\right.\) Bohr's radius)
- A \(5\)
- B \(4\)
- C \(7\)
- D \(8\)
Answer & Solution
Correct Answer
(D) \(8\)
Step-by-step Solution
Detailed explanation
\(2 \pi \mathrm{r}_{\mathrm{u}}=\mathrm{n} \lambda_{\mathrm{d}}\) \(2 \pi \mathrm{a}_0 \frac{\mathrm{n}^2}{\mathrm{z}}=\mathrm{n} \lambda_{\mathrm{d}}\) \(2 \pi \mathrm{a}_0 \frac{4^2}{1}=4 \lambda_{\mathrm{d}}\) \(\lambda_{\mathrm{d}}=8 \pi \mathrm{a}_0\)
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