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JEE Mains · Chemistry · STD 11 - 1. Some basic concept of chemistry

\(5\,g\) of \(NaOH\) was dissolved in deionized water to prepare a \(450\,mL\) stock solution. What volume (in \(mL\) ) of this solution would be required to prepare \(500\,mL\) of \(0.1\,M\) solution? Given : Molar Mass of \(Na\), \(O\) and \(H\) is \(23,16\) and \(1\,g\,mol ^{-1}\) respectively

  1. A \(181\)
  2. B \(182\)
  3. C \(180\)
  4. D \(183\)
Verified Solution

Answer & Solution

Correct Answer

(C) \(180\)

Step-by-step Solution

Detailed explanation

\(M =\frac{5}{40} \times \frac{1000}{450}\) \(M _1 V _1= M _2 V _2\) \(\left(\frac{5}{40} \times \frac{1000}{450}\right) \times V _1=0.1 \times 500\) \(V _1=180\)
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