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JEE Mains · Physics · STD 12 - Dual nature of radiation and matter
  • JEE Mains 2022
  • Medium
  • MCQ

The kinetic energy of emitted electron is \(E\) when the light incident on the metal has wavelength \(\lambda\). To double the kinetic energy, the incident light must have wavelength.

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Answer & Solution

Correct Answer

(B) \(\frac{ hc \lambda}{ E \lambda+ hc }\)

Step-by-step Solution

Detailed explanation

\(E =\frac{ hc }{\lambda}-\phi-\text { (i) }\)

\(2 E =\frac{ hc }{\lambda^{\prime}}-\phi-\) (ii)

(ii) \(-\) (i)

\(E = hc \left(\frac{1}{\lambda^{\prime}}-\frac{1}{\lambda}\right)\)

\(\Rightarrow \lambda^{\prime}=\frac{ hc \lambda}{ E \lambda+ hc }\)

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