JEE Mains · Chemistry · STD 11 - 6.1. Equilibrium - 1 (chemical Equilibrium)
The equilibrium constant for decomposition of \(\mathrm{H}_2 \mathrm{O}(\mathrm{g})\) \(\mathrm{H}_2 \mathrm{O}(\mathrm{~g}) \rightleftharpoons \mathrm{H}_2(\mathrm{~g})+\frac{1}{2} \mathrm{O}_2(\mathrm{~g})\left(\Delta \mathrm{G}^{\circ}=92.34 \mathrm{~kJ} \mathrm{~mol}^{-1}\right)\) is \(8.0 \times 10^{-3}\) at 2300 K and total pressure at equilibrium is 1 bar. Under this condition, the degree of dissociation \((\alpha)\) of water is ________ \(\times 10^{-2}\) (nearest integer value).
[Assume \(\alpha\) is negligible with respect to 1 ]
- A 10
- B 15
- C 5
- D 20
Answer & Solution
Correct Answer
(C) 5
Step-by-step Solution
Detailed explanation
\begin{aligned} & \mathrm{H}_2 \mathrm{O}(\mathrm{g}) \rightleftharpoons \mathrm{H}_{2(\mathrm{~g})}+\frac{1}{2} \mathrm{O}_{2(\mathrm{~g})} \\ & \mathrm{t}=0 \quad 1 \mathrm{~mole} \\ & \mathrm{t}=\mathrm{t}_{\mathrm{eq}} \quad 1-\alpha \quad \alpha \quad \frac{\alpha}{2} \\ &…
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