JEE Mains · Chemistry · STD 11 - 5. Thermodynamics and thermochemistry
\(A _2+ B _2 \rightarrow 2 AB \cdot \Delta H _{ l }^0=-200\,kJmol ^{-1}\) \(AB , A _2\) and \(B _2\) are diatomic molecule. If the bond enthalpies of \(A _2, B _2\) and \(AB\) are in the ratio \(1: 0.5: 1\), then the bond enthalpy of \(A_2\) is \(......\,kJ\,mol ^{-1}\) (Nearest integer)
- A \(600\)
- B \(200\)
- C \(800\)
- D \(500\)
Answer & Solution
Correct Answer
(C) \(800\)
Step-by-step Solution
Detailed explanation
\(A _2+ B _2 \rightarrow 2 AB ; \Delta H _{ r }^0=-200\,kJ\,mol ^{-1}\) \(\Rightarrow \Delta H _{ p }^0( AB )=-200\,kJ\,mol\,m ^{-1}\) \(\therefore \Delta H _{ R }^0\) for reaction \(A _2+ B _2 \rightarrow 2 AB\) is \(-400\,kJ\,mol ^{-1}\) Given: Bond Enthalpy of \(A _2, B _2\)…
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