JEE Mains · Chemistry · STD 12 - 2. Electrochemistry
The cell potential for the following cell \(Pt \left| H _{2}( g )\right| H ^{+}( aq ) \| Cu ^{2+}(0.01 M ) \mid Cu ( s )\) is \(0.576 \,V\) at \(298\, K\). The \(pH\) of the solution is \(......\,.\) (Nearest integer)
- A \(50\)
- B \(5\)
- C \(15\)
- D \(25\)
Answer & Solution
Correct Answer
(B) \(5\)
Step-by-step Solution
Detailed explanation
Anode \(: H _{2} \rightarrow 2 H ^{+}+2 e ^{-}\) Cathode: \(Cu ^{2+}+2 e ^{-} \rightarrow Cu\) \(\overline{ Cu ^{2+}+ H _{2} \rightarrow 2 H ^{+}+ Cu }\) \(E _{\text {cell }}= E _{\text {cell }}^{0}-\frac{0.06}{2} \log \frac{\left[ H ^{+}\right]^{2}}{\left[ Cu ^{2+}\right]}\)…
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